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Re: Passing a list as seperate parameters?



Hi Azumanga,

Apply or"@@" is what you are looking for.

Union @@ {{a,b},{c,d}}

Daniel



Azumanga wrote:

> I have a recuring problem in using mathematica, which I'm sure there

> must be a simple fix for, but I've looked through the manual and can't

> find it.

> 

> As an example, I build up the list { {a,b},{c,d} }, and I want to find

> the union of it's elements.

> 

> At first glance, I want Union. However, Union wants it's input as

> Union[{a,b},{c,d}], Union[{{a,b},{c,d}}] doesn't do anything.

> 

> In general I get around this by fold, but it seems there should be a

> simpler method?

> 

> 




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