(in)dependent variables in DSolve: need explanation.
- To: mathgroup at smc.vnet.net
- Subject: [mg73234] (in)dependent variables in DSolve: need explanation.
- From: P_ter <peter_van_summeren at yahoo.co.uk>
- Date: Thu, 8 Feb 2007 03:40:50 -0500 (EST)
Hello, I have a partial differential equation which I can solve by hand, but not yet in Mathematica. I need an explanation: In queueing theory I have: z dP(z,t)/dt = (1-z)((a - b z)* P(z,t) - bP0(t)) with P(z,0)=z^i (i given). I can take the Laplace transform of the DE: (z^(i+1) - b (1-z)Laplace(P0(t)) --------------------------------- (sz - (1-z)(b - az) The numerator must be zero, so it follows that Laplace(P(0,t)) is known now. The rest is substitution in the first formula and after that taking the inverse. In fact I have the DE and search for solutions such that P0(t) exists. How do I do that in Mathematica with the DE and without applying the Laplace transform? Is that possible? The DE comes from the well known Markov equation for a single channel Poisson input, and exponential holding time. Its equation starts with dPo/dt = -a Po(t) + b P1(t) and the rest: dPn/dt=aPn-1(t)-(a+b)Pn(t)+bPn+1(t). The above used P(z,t) is the generating function of Pn: P(z,t) = Sum from zero to infinity (Pn(t) z^n). Well one can find it in Saaty's Elements of Queueing Theory, page 88. It is a standard procedure. I now would like to do it in Mathematica, and my basic question is: can it be done with DSolve only.