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MathGroup Archive 2007

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Re: How to parse result from Reduce[ ] function

  • To: mathgroup at smc.vnet.net
  • Subject: [mg73286] Re: How to parse result from Reduce[ ] function
  • From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
  • Date: Fri, 9 Feb 2007 02:30:58 -0500 (EST)
  • Organization: Uni Leipzig
  • References: <eqep0l$5bs$1@smc.vnet.net>
  • Reply-to: kuska at informatik.uni-leipzig.de

Hi,

{x,y,p}/. (Cases[youResult,_Equal] /. Equal->Rule)

???

or

{x,y,p}/. Solve[Cases[youResult,_Equal],{x,y,p}]

Regards
   Jens

Anton Vrba wrote:
> Hi,
>  
> The output of a Reduce[...] function call is
>  
> C[1](element)Integers &&
> x==358537039003+2964364736430689 C[1] &&
> y==28744265823+237656026328741 C[1] &&
> p==205319+1697566324 C[1]
>  
> but I want to use the values  after the p== i.e. 205319 and 1697566324 for further calculation in my program
>  
> How do I obtain these? other than by manual cut and paste.
>  
> Thanks for your help
> best regards
> Anton
> 


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