Showing that ArcSinh[2]/ArcCsch[2] is 3?

*To*: mathgroup at smc.vnet.net*Subject*: [mg73499] Showing that ArcSinh[2]/ArcCsch[2] is 3?*From*: "David W.Cantrell" <DWCantrell at sigmaxi.net>*Date*: Tue, 20 Feb 2007 06:19:31 -0500 (EST)

I hope I've just overlooked something very simple. I want to transform ArcSinh[2]/ArcCsch[2] to 3, using just "knowledge" already implemented in Mathematica. I tried FullSimplify first, and it doesn't help. I tried several other things. For example, TrigToExp[ArcSinh[2]/ArcCsch[2]] yields Log[2 + Sqrt[5]]/Log[1/2 + Sqrt[5]/2]. But then how should we transform that to 3? David

**Follow-Ups**:**Re: Showing that ArcSinh[2]/ArcCsch[2] is 3?***From:*János <janos.lobb@yale.edu>

**Re: Showing that ArcSinh[2]/ArcCsch[2] is 3?***From:*Andrzej Kozlowski <akoz@mimuw.edu.pl>