Mathematica 9 is now available
Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
2007
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 2007

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Showing that ArcSinh[2]/ArcCsch[2] is 3?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg73518] Re: [mg73499] Showing that ArcSinh[2]/ArcCsch[2] is 3?
  • From: János <janos.lobb at yale.edu>
  • Date: Wed, 21 Feb 2007 01:40:10 -0500 (EST)
  • References: <200702201119.GAA07770@smc.vnet.net>

On Feb 20, 2007, at 6:19 AM, David W.Cantrell wrote:

> I hope I've just overlooked something very simple.
> I want to transform ArcSinh[2]/ArcCsch[2] to 3, using just "knowledge"
> already implemented in Mathematica. I tried FullSimplify first, and it
> doesn't help. I tried several other things. For example,
>
> TrigToExp[ArcSinh[2]/ArcCsch[2]]  yields
>
> Log[2 + Sqrt[5]]/Log[1/2 + Sqrt[5]/2].
>
> But then how should we transform that to 3?
>
> David

My newbie instinct say that

IntegerPart[N[t]]+1

will do it :)

where t=ArcSinh[2]/ArcCsch[2]

Of course if you want just Real 3, than

N[t]

can be a friend.

J=E1nos


----------------------------------------------
Trying to argue with a politician is like lifting up the head of a 
corpse.
(S. Lem: His Master Voice)



  • Prev by Date: Re: Precision issues
  • Next by Date: Re: Precision of a number raised to a power
  • Previous by thread: Re: Showing that ArcSinh[2]/ArcCsch[2] is 3?
  • Next by thread: Re: Showing that ArcSinh[2]/ArcCsch[2] is 3?