Re: split again
- To: mathgroup at smc.vnet.net
- Subject: [mg73651] Re: split again
- From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
- Date: Sat, 24 Feb 2007 02:07:27 -0500 (EST)
- Organization: Uni Leipzig
- References: <ermd8n$hmd$1@smc.vnet.net>
- Reply-to: kuska at informatik.uni-leipzig.de
Hi,
you have forgotten a & and you mean
zSplit=Split[z,#1<=0.7 === #2>=0.7 &];
To get all sublists with Length[] >= n try
With[{n=2},
Reap[If[Length[#] >= n, Sow[#]] & /@ zSplit][[2]]
]
and to get the first one
With[{n=2},
Catch[If[Length[#] >= n, Throw[#]] & /@ zSplit]
]
Regards
Jens
Arkadiusz.Majka at gmail.com wrote:
> Hi,
>
> Thank you very much for your help in my provious post. Now, consider
> please a list
>
> z=Table[Random[],{1000}];
>
> zSplit=Split[z,#1<=0.7 === #2>=0.7]; (bulit thanks to your
> help)
>
> I want to pick the first sublist of zSplit that consists of elements
> <= 0.7 and whose length is greater than a certain number (say 5). I
> think that a good candidate would be using Cases and variations of _ ,
> but I don't know how.
>
> What I want to do (and what my both posts are about) is to find the
> first sublist of z with all elements less than A and the length of
> this sublist must be greater than B. Maybe there exists better
> solution than to Split z in advance since what I need to do in my next
> step is to find ONLY the FIRST sublist of splitted z.
>
> Thanks again,
>
> Arek
>
>