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Re: Can Mathematica do Separation of Variables?
*To*: mathgroup at smc.vnet.net
*Subject*: [mg73016] Re: Can Mathematica do Separation of Variables?
*From*: Paul Abbott <paul at physics.uwa.edu.au>
*Date*: Mon, 29 Jan 2007 04:19:35 -0500 (EST)
*Organization*: The University of Western Australia
*References*: <epf9mr$c44$1@smc.vnet.net>
In article <epf9mr$c44$1 at smc.vnet.net>, "Raj" <rajanikanth at gmail.com>
wrote:
> Can somebody please tell me if Mathematica can do separation of
> variables (using DSolve)
>
> for ex: if I give this equation to DSolve, its not able to separate the
> variables
>
> D[u[x,t],{t,2}]==D[u[x,t],{x,2}]+D[u[x,t],{t,1},{x,2}]
There is no built-in tool for separation of variables. However, for your
differential equation,
deq = D[u[x,t],{t,2}] == D[u[x,t],{x,2}]+D[u[x,t],{t,1},{x,2}];
re-writing this as
deq = Subtract @@ deq
followed by the substitution u -> Function[{x, t}, X[x] T[t]],
deq /. u -> Function[{x, t}, X[x] T[t]];
and then by dividing through by X[x] (T'[t] + T[t])) generates the
separated equations:
Apart[% / (X[x] (T'[t] + T[t]))]
T''[t]/(T[t] + T'[t]) - X''[x]/X[x]
There is another approach for such equations. One can find travelling
wave solutions of the form u[x,t] = g[x - v t] as follows:
deq /. u -> Function[{x, t}, g[x - v t]] // Simplify
(v^2 - 1) g''[x - v t] + v g'''[x - v t] == 0
Putting x - v t -> z, the solution is immediate:
DSolve[% /. x - v t -> z, g, z]
{{g -> Function[{z}, -((v^2*C[1])/(E^(((-1 + v^2)*z)/v)*(1 - v^2)*
(-1 + v^2))) + C[2] + z*C[3]]}}
Cheers,
Paul
_______________________________________________________________________
Paul Abbott Phone: 61 8 6488 2734
School of Physics, M013 Fax: +61 8 6488 1014
The University of Western Australia (CRICOS Provider No 00126G)
AUSTRALIA http://physics.uwa.edu.au/~paul
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