Re: Graphics package in v6
- To: mathgroup at smc.vnet.net
- Subject: [mg78470] Re: Graphics package in v6
- From: dh <dh at metrohm.ch>
- Date: Mon, 2 Jul 2007 06:57:53 -0400 (EDT)
- References: <f65aq2$9jg$1@smc.vnet.net>
Hi Florian,
see below, Daniel
Jaccard Florian wrote:
> Dear group,
>
> I'm a convinced Mathematica user, I love the new features I discover in v6, but I think the Graphics package was very useful in v5 and I'm missing it.
>
> For example, it was very easy to obtain the 3D plot of a surface of revolution around the x-axis with SurfaceOfRevolution.
>
> Let us take the revolution of y=x^2 around the x-axis :
>
> << "Graphics`"
> SurfaceOfRevolution[x^2, {x, 0, 2}, RevolutionAxis -> {1, 0, 0}]
>
> Not possible without cheating if using RevolutionPlot3D, isn't it=A0?
you either need the following form of RevolutionPlot3D:
RevolutionPlot3D[{z^2, z}, {z, 0, 1}]
or you need the inverse function of x^2 Sqrt[x]:
RevolutionPlot3D[Sqrt[x], {x, 0, 1}]
>
> Or you could have a nice plot of implicit functions, with the ticks on the x- and y-axis, using ImplicitPlot...
>
> Example :
>
> << "Graphics`"
> ImplicitPlot[x^3*y + x*y^3 == 2, {x, -3, 3}, {y, -3, 3}]
>
> Not possible using CountourPlot without cheating, isn't it?
why does ContourPlot not work? The only difference I see is that the
axes are outside the plot.:
ContourPlot[x^3*y + x*y^3 == 2, {x, -3, 3}, {y, -3, 3}]
>
> (I consider the following as cheating :
> Show[Plot[0, {x, -3, 3}, PlotRange -> {-3, 3},
> AspectRatio -> Automatic],
> ContourPlot[x^3*y + x*y^3 == 2, {x, -3, 3}, {y, -3, 3},
> Axes -> True,
> AxesOrigin -> {0, 0}, PerformanceGoal -> "Quality",
> PlotPoints -> 150]]
> )
>
> I tried: it still works in v6, but the whole package is declared obsolete, and there is no help anymore available.
>
> Am I missing something? Or am I the only guy who would appreciate the re-apparition of some lost features in the future v.6.1?
>
> Reactions welcome!
>
> Regards
>
> Florian Jaccard
>
>
>
>