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Re: Plot without Show

  • To: mathgroup at smc.vnet.net
  • Subject: [mg79252] Re: Plot without Show
  • From: dimitris <dimmechan at yahoo.com>
  • Date: Sun, 22 Jul 2007 04:20:52 -0400 (EDT)
  • References: <f7si4b$1qs$1@smc.vnet.net>

On 21     , 12:03, Philipp <kitsc... at romandie.com> wrote:
> Hello
> Thanks to all who answered my original question!
>
> Just to respond to D.S.A
>
> > MathGroup is the propper place for asking questions
> > about Mathematica.
> > But why don't you spend a little more time with the
> > Help Broswer?
> > The benefits will be many...
> > You can learn a program without reading its help
> > (the more the better!)
>
> I think this a bit unfair. I do _always_ spend time searching help files and googling to get answers to my question before posting to a public forum.
>
> But mathematica's help browser is also not making it easy to find the things you are looking for.
>
> You are basically telling me I should have looked up DisplayFunction in the help file. But this supposes that I knew that the magic word is DisplayFunction.
>
> The help file for Plot does not mention it (oh yes it's listed with the 30 other options as a result of Options[Plot]). The corresponding book section 1.9.1 does not mention it. Show's help mentions that "The option DisplayFunction determines the actual output mechanism used." which basically doesn't give a clue what it means. It also says "Functions like Plot automatically apply Show to the graphics expressions they generate. "
>
> Well, you can tell that I got that far because my subject was "Plot without Show".
>
> That you have to call Show to not show something did not cross my mind, I must admit.
>
> Best regards

I apologize if I sound elitistic and unfair.
Many times questions in the same vein are asked
by newbies. But you seem that you have done
all of the proper search before consult to the forum.

However, all that I mean that searching a little more the
documentation of a built in function (including the documentation
of its options and attributes (if there are)) may give you the
requested
answer.

BTW, I have found very useful the following function

In[95]:=
Clear[Opts]

Opts[o_(*Mathematica Symbol*)] := (Information[Evaluate[#1[[1]]]] & ) /
@ Options[o]

Try for example

In[98]:=
Opts[Plot];

In[99]:=
Opts[Trace];

In[103]:=
Opts[Integrate];

In[104]:=
Opts[Trace];

In[107]:=
Opts[Plot3D];

Dimitris





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