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Re: Re: curve fit for exp function

• To: mathgroup at smc.vnet.net
• Subject: [mg79357] Re: [mg79325] Re: curve fit for exp function
• From: Martin Channon <mgcqso at comcast.net>
• Date: Wed, 25 Jul 2007 02:13:52 -0400 (EDT)
• References: <f7v54b$t9b$1@smc.vnet.net><f81n1j$m5j$1@smc.vnet.net> <200707241010.GAA26416@smc.vnet.net>

Hey folks, I'd like to ask for some more help, but this would be on a 
consulting-fee basis. I am trying to fit a certain set of points with an 
exp function. I have curve fitting software, but it can't handle the 
problem. I understand that it is possible to write a program in 
Mathematica to do this sort of thing. I don't know how to do it myself, 
and I don't want to spend the time trying to learn how. I'd rather pay 
someone who already knows . What makes the problem defeat my curve 
fitting software is that the points are expressed with many decimal 
places, for example, 9.9999999995. I need to fit this with a function 
that is nearly zero along  the interval -50 < X <9.99 and then rises 
sharply. I have pretty much the ideal function. It is Y = 
a*Exp[-b(X-10)^c]. The points are subject to modification, but here is a 
typcial set:

10
9.999999997
9.999999993
9.999999986
9.999999977
9.999999963
9.999999939
9.999999886
9.999999678
9.999999566

This is bell-shaped curve; it goes down again on the right after 
reaching a peak, but the right side doesn't matter for me. This is worth 
$100 to me even if you can do it in five minutes. I would want to be 
able to insert the points and get back a, b and c. Actually, the exp 
part could also be made a parameter. Anybody interested in some pocket 
change? I can send payment via PayPal.

• Follow-Ups:
  • Re: Re: Re: curve fit for exp function
    • From: Martin Channon <mgcqso@comcast.net>

• References:
  • Re: export data to spreadsheet
    • From: Jean-Marc Gulliet <jeanmarc.gulliet@gmail.com>