Re: Question re: graphics primitives

*To*: mathgroup at smc.vnet.net*Subject*: [mg77634] Re: Question re: graphics primitives*From*: Jean-Marc Gulliet <jeanmarc.gulliet at gmail.com>*Date*: Thu, 14 Jun 2007 05:24:19 -0400 (EDT)*Organization*: The Open University, Milton Keynes, UK*References*: <f4omi2$7jr$1@smc.vnet.net>

Ghuloum, Anwar wrote: > Is it possible to put conditional clauses (i.e. If[.]) in the > VertexRenderingFunction option for TreeForm (or any primitive that this > option applies to)? I wanted to selectively label vertices based on label > content, but Mathematica was complaining that "If" is not a graphics > primitive or directive. > > > > (Basically, I'm trying to draw a tree where only the leaves have labels: > > TreeForm[{{a, b}, {c, {d}}}, VertexRenderingFunction -> (If[#2 == List, {}, > Text[#2, #1]] &)] > > ) > > > > In general, I was having a hard time finding information at the > documentation center on the limitations on how I can generate graphics > primitives.but perhaps I'm not looking in the right place. > > > Thanks in advance! > > -- > > Anwar Ghuloum > > Microprocessor Technology Lab, Intel > > > Below we define a function with some conditions on it. In doing so, Mathematica sees only graphic primitive whenever it evaluates the VertexRenderingFunction option. (Arguably, the following example is written in a more Mathematica fashion.) If the second argument is a list, then the first definition (the less general definition indeed) is evaluated and the empty list is returned. Otherwise, the more general definition (the second in our case) is called and the graphic primitive Text is returned. myRender[r_, k_] := {} /; k == List myRender[r_, k_] := Text[k, r] TreeForm[{{a, b}, {c, {d}}}, VertexRenderingFunction -> (myRender[#1, #2] & )] Regards, Jean-Marc