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MathGroup Archive 2007

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two integrals

  • To: mathgroup at
  • Subject: [mg78309] two integrals
  • From: dimitris <dimmechan at>
  • Date: Thu, 28 Jun 2007 04:21:03 -0400 (EDT)

Any ideas about getting a closed form expression?
No need fo convegrence; a result valid in the Hadamard sense is ok!

Integrate[(Sqrt[1 + m^2*u^2]/u)*Exp[(-y)*(Sqrt[1 + m^2*u^2]/m)]*
  Sin[u*x], {x, 0, Infinity}]

Integrate[Exp[(-y)*(Sqrt[1 + m^2*u^2]/m)]*Cos[u*x], {x, 0, Infinity}]


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