Re: Means

*To*: mathgroup at smc.vnet.net*Subject*: [mg73939] Re: Means*From*: "JGBoone at gmail.com" <JGBoone at gmail.com>*Date*: Sat, 3 Mar 2007 01:12:27 -0500 (EST)*References*: <es9295$3na$1@smc.vnet.net>

Yeah Bob that line you gave me does the same as N[Mean[Map[Last, list]]]. It goes to the second part of the pair and takes the average of all. I want to take only the average of the last half of the last half. So i have 3000 pairs that look like {a,b} i've got a way to take the means of all the b's in list of 3000. but i want to take the mean's of the last 1500 b's.