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Re: Problems with simplify and Sqrt[a^2]
Sqrt[a^2] is equal to a only for Re[a]>0; for Re[a]<0 it is -a. So Mathematica is being careful and not making assumptions that could end up giving a wrong result. You can get what you want by using PowerExpand. In:= PowerExpand[v3/Sqrt[v1^2]/Sqrt[v2^2] - v3/v1/v2] Out= 0 Another way is to use Simplify (or FullSimplify) with assumptions: Simplify[expression, v1>0 && v2>0 && ...] Bhuvanesh, Wolfram Research.