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Re: Replacing list elements while retaining structure

Is this what you want? :

structurize[a_List, b_List] := a /. Thread[Flatten[a] -> b];


On 4 Mrz., 05:50, "D. Grady" <D.C.Gr... at> wrote:
> Okay, so I have two lists, X and Y.  X has some complex structure
> which is important, but the values contained in X are not important.
> Y has values that are important, but the structure of Y is not.  I was
> to sequentially replace all the elements in X with the elements of Y.
> It's assumed that X and Y have the same total number of elements, i.e.
> Length[Flatten[X]] == Length[Flatten[Y]]
> Here is an example:
> In[8]:=
> structurize[{x,x,{{x},x},x},{1,2,3,4,5}]
> Out[8]=
> {1,2,{{3},4},5}
> This is what I have so far:
> structurize[X_List, Y_List] := ReplacePart[X, Flatten[Y], Position[X,
> a_ /; \
> (Head[a] =!= List), Heads -> False],
>       Table[{i}, {i, 1, Length[
>         Flatten[Y]]}]] /; Length[Flatten[X]] == Length[Flatten[Y]]
> This works fine so long as the elements of X are atomic expressions;
> however, if there is an element of X which is a more complicated
> expression, like x^2, then this function does not work as desired
> because the pattern in Position[] matches x^2 as well as x and 2.  Is
> there a way to avoid matching parts of a subexpression?  Is there a
> better way to approach the problem from the get-go?
> Thanks in advance!

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