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Re: Boundary Conditions in PDE


bar at ANTYSPAM.ap.krakow.pl wrote:
> I have a problem with defining boundaru conditions id NDSolve 
> of PDE
> F is function of [x,t] 
> Conditions has form : (d/dx)F[0,t]==0;
> 
> I wrote this in form : D[F[0,t],x]==0 
> Its TRUE  (0==0)
> 
> Then i wrote D[F[x,t],x]
> out: F(1,0)[x,t] ;    {(1,0) looks like "power"}
> 
> And "copy"&"paste", and changed x to 0 in arguments
> 
> This way works, but I'm sure is a better way ? 
> 
> Regards, Olaf
>  
> 

Write your boundaries conditions as in In[3]:

In[1]:=
D[F[x,t],x]

Out[1]=
  (1,0)
F     [x, t]

In[2]:=
%//FullForm

Out[2]//FullForm=
Derivative[1, 0][F][x, t]

In[3]:=
Derivative[1,0][F][0,t] == 0

Out[3]=
  (1,0)
F     [0, t] == 0

Regards,
Jean-Marc


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