Re: Boundary Conditions in PDE

*To*: mathgroup at smc.vnet.net*Subject*: [mg74330] Re: Boundary Conditions in PDE*From*: Jean-Marc Gulliet <jeanmarc.gulliet at gmail.com>*Date*: Mon, 19 Mar 2007 01:57:16 -0500 (EST)*Organization*: The Open University, Milton Keynes, UK*References*: <etik9a$j4q$1@smc.vnet.net>

bar at ANTYSPAM.ap.krakow.pl wrote: > I have a problem with defining boundaru conditions id NDSolve > of PDE > F is function of [x,t] > Conditions has form : (d/dx)F[0,t]==0; > > I wrote this in form : D[F[0,t],x]==0 > Its TRUE (0==0) > > Then i wrote D[F[x,t],x] > out: F(1,0)[x,t] ; {(1,0) looks like "power"} > > And "copy"&"paste", and changed x to 0 in arguments > > This way works, but I'm sure is a better way ? > > Regards, Olaf > > Write your boundaries conditions as in In[3]: In[1]:= D[F[x,t],x] Out[1]= (1,0) F [x, t] In[2]:= %//FullForm Out[2]//FullForm= Derivative[1, 0][F][x, t] In[3]:= Derivative[1,0][F][0,t] == 0 Out[3]= (1,0) F [0, t] == 0 Regards, Jean-Marc