Re: Boundary Conditions in PDE

• To: mathgroup at smc.vnet.net
• Subject: [mg74330] Re: Boundary Conditions in PDE
• From: Jean-Marc Gulliet <jeanmarc.gulliet at gmail.com>
• Date: Mon, 19 Mar 2007 01:57:16 -0500 (EST)
• Organization: The Open University, Milton Keynes, UK
• References: <etik9a\$j4q\$1@smc.vnet.net>

```bar at ANTYSPAM.ap.krakow.pl wrote:
> I have a problem with defining boundaru conditions id NDSolve
> of PDE
> F is function of [x,t]
> Conditions has form : (d/dx)F[0,t]==0;
>
> I wrote this in form : D[F[0,t],x]==0
> Its TRUE  (0==0)
>
> Then i wrote D[F[x,t],x]
> out: F(1,0)[x,t] ;    {(1,0) looks like "power"}
>
> And "copy"&"paste", and changed x to 0 in arguments
>
> This way works, but I'm sure is a better way ?
>
> Regards, Olaf
>
>

Write your boundaries conditions as in In[3]:

In[1]:=
D[F[x,t],x]

Out[1]=
(1,0)
F     [x, t]

In[2]:=
%//FullForm

Out[2]//FullForm=
Derivative[1, 0][F][x, t]

In[3]:=
Derivative[1,0][F][0,t] == 0

Out[3]=
(1,0)
F     [0, t] == 0

Regards,
Jean-Marc

```

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