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MathGroup Archive 2007

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Re: Boundary Conditions in PDE

  • To: mathgroup at smc.vnet.net
  • Subject: [mg74350] Re: Boundary Conditions in PDE
  • From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
  • Date: Mon, 19 Mar 2007 02:08:04 -0500 (EST)
  • References: <etik9a$j4q$1@smc.vnet.net>

Hi,

and

Derivative[1,0][F][0,t]

does not work ??

Regards
   Jens

bar at ANTYSPAM.ap.krakow.pl wrote:
> I have a problem with defining boundaru conditions id NDSolve 
> of PDE
> F is function of [x,t] 
> Conditions has form : (d/dx)F[0,t]==0;
> 
> I wrote this in form : D[F[0,t],x]==0 
> Its TRUE  (0==0)
> 
> Then i wrote D[F[x,t],x]
> out: F(1,0)[x,t] ;    {(1,0) looks like "power"}
> 
> And "copy"&"paste", and changed x to 0 in arguments
> 
> This way works, but I'm sure is a better way ? 
> 
> Regards, Olaf
>  
> 


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