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MathGroup Archive 2007

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Re: averaging sublists of different lengths

  • To: mathgroup at smc.vnet.net
  • Subject: [mg75527] Re: averaging sublists of different lengths
  • From: dantimatter <dantimatter at gmail.com>
  • Date: Fri, 4 May 2007 04:13:30 -0400 (EDT)
  • References: <200705020747.DAA04729@smc.vnet.net><f1c4vl$h98$1@smc.vnet.net>

wow!  thanks to all for the responses.  i guess the problem was easier
to solve than i thought.  :)
cheers,
dan


On May 3, 3:03 am, bsyeh... at gmail.com wrote:
> call your list l
>
> then
> With[{ml = Max[Length /@ l]},
>  Table[Mean[Flatten[Map[If[Length[#] >= i, #[[i]], {}] &, l]]], {i,
>    ml}]]
>
> so for your data the result is
> {686/11, 692/11, 710/11, 716/11, 714/11, 706/11, 328/5, 257/4,
>  456/7,
>    502/7, 212/3, 74, 250/3, 80, 74, 64, 88, 56}
>
> regards
> yehuda
>
> On 5/2/07, dantimatter <dantimat... at gmail.com> wrote:
>
>
>
> > Hello all,
>
> > I have a list of lists like this:
>
> > {{70, 66, 64, 68, 64, 56, 68, 78, 62, 68, 84}, {70, 64, 64, 56, 66,
> > 56, 62,
> >     64, 66, 88, 54, 72}, {58, 54, 54, 60, 72, 70, 62, 68, 74, 76, 70},
> > {66,
> >     56, 60, 64, 56, 62, 68, 58, 58, 58, 68, 76, 62, 76, 66, 64, 88,
> > 56}, {56,
> >     64, 72, 72, 70, 62, 76, 76, 76, 76, 86, 80, 100}, {60, 60, 70, 68,
> > 60, 60,
> >      50, 56, 60, 70, 62, 68, 88, 84, 82}, {54, 66, 72, 62, 70, 66,
> > 70,
> >     56}, {60, 60, 60, 62, 74, 80, 70}, {54, 62, 64, 72, 76, 74}, {66,
> > 74, 70,
> >     80, 54, 54, 64}, {72, 66, 60, 52, 52, 66, 66, 58, 60, 66}}
>
> > What I'd really like is the average all the 1st values, 2nd values,
> > etc, but I'm having trouble figuring out how to deal with the fact
> > that the lists are not all the same length.   Is there a way to drop
> > the sublists as they run out of points to add to the average, i.e. if
> > I want the average of all the nth values, but Length[shortSublist] <
> > n, can I somehow drop shortSublist and then calculate the average from
> > the other sublists?
>
> > Also, the Mean[] function requires more than one data point, but I'd
> > still like to extract out the values for which there is only one data
> > point.  Is there a way to do this?
>
> > Thanks!
> > dan




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