Re: Using FindFit with constraints ??
- To: mathgroup at smc.vnet.net
- Subject: [mg75701] Re: [mg75655] Using FindFit with constraints ??
- From: Carl Woll <carlw at wolfram.com>
- Date: Wed, 9 May 2007 04:20:27 -0400 (EDT)
- References: <200705080945.FAA18382@smc.vnet.net>
Alex wrote: >Hello everybody, > >I saw at http://reference.wolfram.com/mathematica/ref/FindFit.html >that FindFit can be used with constraints for the parameters. However >when I try the example with Mathematica 5.2 I get an error. > > > The problem is that you are looking at version 6 documentation and expecting version 5.2 to have the same functionality. FindFit with constraints is a new version 6 feature. Carl Woll Wolfram Research >model = a Cos[=CF=89 t]; >data = Table[{t, Cos[2.1 t]}, {t, 0, 10, .25}] + RandomReal[.1, 41]; >fit = FindFit[data, {model, {a > 0, 1 < =CF=89 < 2}}, {a, =CF=89}, t] > >=> >FindFit::nlnum: The function value {-1. + Cos[RandomReal[0.1, 41.]] - >\ >1=2E\RandomReal[0.1, 41.], \[LeftSkeleton]9\[RightSkeleton], \ >[LeftSkeleton]113\ >\[RightSkeleton]} is not a list of numbers with dimensions {123} at >{a, =CF=89} = \ >{1, 1}. > > >What am I doing wrong ?? > >Alex > > >
- References:
- Using FindFit with constraints ??
- From: Alex <axel.kowald@rub.de>
- Using FindFit with constraints ??