|
[Date Index]
[Thread Index]
[Author Index]
Using FindFit with constraints ??
- To: mathgroup at smc.vnet.net
- Subject: [mg75655] Using FindFit with constraints ??
- From: Alex <axel.kowald at rub.de>
- Date: Tue, 8 May 2007 05:45:28 -0400 (EDT)
Hello everybody,
I saw at http://reference.wolfram.com/mathematica/ref/FindFit.html
that FindFit can be used with constraints for the parameters. However
when I try the example with Mathematica 5.2 I get an error.
model = a Cos[=CF=89 t];
data = Table[{t, Cos[2.1 t]}, {t, 0, 10, .25}] + RandomReal[.1, 41];
fit = FindFit[data, {model, {a > 0, 1 < =CF=89 < 2}}, {a, =CF=89}, t]
=>
FindFit::nlnum: The function value {-1. + Cos[RandomReal[0.1, 41.]] -
\
1=2E\RandomReal[0.1, 41.], \[LeftSkeleton]9\[RightSkeleton], \
[LeftSkeleton]113\
\[RightSkeleton]} is not a list of numbers with dimensions {123} at
{a, =CF=89} = \
{1, 1}.
What am I doing wrong ??
Alex
Prev by Date:
Re: What happened to the
Next by Date:
Re: Pi upto a Billion Digits
Previous by thread:
Re: Adaptive Monte Carlo integration algorithm(s) in Mathematica6
Next by thread:
Re: Using FindFit with constraints ??
|