Re: v. 6, third argument to rectangle

*To*: mathgroup at smc.vnet.net*Subject*: [mg76687] Re: v. 6, third argument to rectangle*From*: dimitris <dimmechan at yahoo.com>*Date*: Sat, 26 May 2007 04:19:24 -0400 (EDT)*References*: <f21e5e$6e7$1@smc.vnet.net>

I think the following was not mentioned. Since you are interested in putting two graphs side by side what is bad with the following In[73]:= Block[{$DisplayFunction = Identity}, g1 = Plot[o^(1/2), {o, 1, 2}, PlotStyle -> Red]; g2 = Plot[Log[o], {o, 1, 2}, PlotStyle -> Blue]; ] Show[GraphicsArray[{g1, g2}], ImageSize -> 600] It works in version 5.2 and I think there will not be any problem in version 6. (confirmation needed!) Dimitris / rip pelletier : > hi, > > thru 5.2 we could display, for example, 2 graphs side-by-side by using a > third argument to Rectangle, the name of a graphics object. > > 6.0 tells me that i cannot call Rectangle with 3 arguments. (true, it > was a bit of a kludge, and in principle i approve of it going away, > but....) > > what is the replacement? > > thanks, > rip > > -- > NB eddress is r i p 1 AT c o m c a s t DOT n e t