Re: What is #6 to SphericalPlot3D[]

• To: mathgroup at smc.vnet.net
• Subject: [mg83053] Re: What is #6 to SphericalPlot3D[]
• From: dh <dh at metrohm.ch>
• Date: Fri, 9 Nov 2007 05:09:08 -0500 (EST)
• References: <fguqla\$q7h\$1@smc.vnet.net>

```
Hi Roger,

(#6 > 0.95 &) is a function that returns True if its 6'th argument is

bigger than 0.95, False otherwise. If you use:

RegionFunction->(Print[{##}]&) in SpericalPlot3D

you will see that the 6'th argument is the length if the first 3

arguments, I guess the distance from the origin.

hope this helps, Daniel

congruentialuminaire at yahoo.com wrote:

> Hello Mathematica UG:

>

> I was doing some experiments with this function. In the help there is

> an example using RegionFunction -> (#6 > 0.95 &). I cannot find this

> documented anywhere. Is this documented?

>

> I think I remember that there are 6 corrds in a spherical coordinate

> system (or spherical transformation??). If so, is #6 = r cos(theta)?

>

> TIA.

>

> Regards..Roger

>

>

```

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