Re: DataRange

*To*: mathgroup at smc.vnet.net*Subject*: [mg83548] Re: DataRange*From*: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>*Date*: Thu, 22 Nov 2007 04:59:50 -0500 (EST)*Organization*: Uni Leipzig*References*: <fi0q05$6ib$1@smc.vnet.net>*Reply-to*: kuska at informatik.uni-leipzig.de

Hi, insert the correct x-values ? with With[{dx1 = 0.5}, fullData1 = MapIndexed[{#2[[1]]*dx1, #1} &, data1] ] With[{dx2 = 0.5}, fullData2 = MapIndexed[{#2[[1]]*dx2, #1} &, data2] ] ListPlot[{fullData1, fullData2}] clear ly you have to insert for dx1 and dx2 the values you have .. Regards Jens thomas wrote: > Hello Mathgroup, > > I use ListLinePlot to plot some data that has been downsampled. In > order to get the original time-range of the data represented correctly > on the x-axis, I use DataRange->{1,Length-of-original-data}, which > works just beautifully. > > Now imagine I want to plot 2 sets of data with different original > length, both have been downsampled. As far as I know, I cannot use the > DataRange option anymore, because it will equally apply to both > curves, therefore either stretching or compressing one curve relative > to the other. > > Example: > data1 = Range[5];(*imagine original length is 50*) > data2 = .5 Range[10];(*imagine original length is 100*) > ListLinePlot[{data1, data2}, Frame -> True, AspectRatio -> Full, > PlotLabel -> "Correct relative scale of data"] > ListLinePlot[{data1, data2}, DataRange -> {1, 50}, Frame -> True, > AspectRatio -> Full, PlotLabel -> "data2 is compressed"] > ListLinePlot[{data1, data2}, DataRange -> {1, 100}, Frame -> True, > AspectRatio -> Full, PlotLabel -> "data1 is streched"] > > > Is there an easy way to do this, short of creating specific {x,y}- > pairs for each data point in each of the curves? > > As a suggestion to WRI I would propose that one should be able to give > multiple inputs to DataRange, to handle these issues, similar to way > the option PlotStyle->...handles the directives given to it. > > thomas >