Solving Inequality

• To: mathgroup at smc.vnet.net
• Subject: [mg82680] Solving Inequality
• From: Quang Nguyen <quangn at gmail.com>
• Date: Sun, 28 Oct 2007 04:03:19 -0500 (EST)

```Dear all,

My friend has the following code to solve a system of nonlinear inqualities. She can run it on her laptop. However, when I run on my laptop there was a message saying that "0.1 is not a variable". Where 0.1 is the valua that was initially assigned to an unknown parameter in the inquality system. I would highly appreciate if you can explain why this might be the case.

Many thanks!

Quang

Here is the code:

<< "Algebra`InequalitySolve`"
c2 = 580
c3 = 600

b1 = 50
c1 = 400
d1 = 100
p1 = .1
r1 = .3
a2 = 400
b2 = 300
d2 = 50
p2 = .9
r2 = .7
\[Alpha]1 = .1
\[Alpha]2 = .2
\[Alpha]3 = .3
\[Alpha]4 = .4
\[Alpha]5 = .5
\[Alpha]6 = .6
\[Alpha]7 = .7
\[Alpha]8 = .8
\[Alpha]9 = .9
\[Alpha]10 = 1
\[Alpha]11 = 1.1
\[Alpha]12 = 1.2
\[Alpha]13 = 1.3
\[Alpha]14 = 1.4
\[Alpha]15 = 1.5
(*0-15*)
a1 = 30
a3 = 680
b = 0
\[Gamma] = 0.1
InequalitySolve[{a1^\[Alpha]1*(Exp[-(-Log[p1])^\[Gamma]]) +
b1^\[Alpha]1*(1 - Exp[-(-Log[p1])^\[Gamma]]) <
c1^\[Alpha]1*(Exp[-(-Log[r1])^\[Gamma]]) +
d1^\[Alpha]1*(1 - Exp[-(-Log[r1])^\[Gamma]]),
a3^\[Alpha]1*(Exp[-(-Log[p1])^\[Gamma]]) +
b1^\[Alpha]1*(1 - Exp[-(-Log[p1])^\[Gamma]]) >
c1^\[Alpha]1*(Exp[-(-Log[r1])^\[Gamma]]) +
d1^\[Alpha]1*(1 - Exp[-(-Log[r1])^\[Gamma]]),
a2^\[Alpha]1*(Exp[-(-Log[p2])^\[Gamma]]) +
b2^\[Alpha]1*(1 - Exp[-(-Log[p2])^\[Gamma]]) >
c2^\[Alpha]1*(Exp[-(-Log[r2])^\[Gamma]]) +
d2^\[Alpha]1*(1 - Exp[-(-Log[r2])^\[Gamma]]),
a2^\[Alpha]1*(Exp[-(-Log[p2])^\[Gamma]]) +
b2^\[Alpha]1*(1 - Exp[-(-Log[p2])^\[Gamma]]) <
c3^\[Alpha]1*(Exp[-(-Log[r2])^\[Gamma]]) +
d2^\[Alpha]1*(1 -
Exp[-(-Log[r2])^\[Gamma]])}, {\[Gamma], \[Alpha]1, b}]

```

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