Re: Problem with inverse laplace transform (FIX)
- To: mathgroup at smc.vnet.net
- Subject: [mg81150] Re: Problem with inverse laplace transform (FIX)
- From: Jean-Marc Gulliet <jeanmarc.gulliet at gmail.com>
- Date: Fri, 14 Sep 2007 03:32:51 -0400 (EDT)
- Organization: The Open University, Milton Keynes, UK
- References: <fcb48a$fos$1@smc.vnet.net>
Alexey Nikitin wrote:
<snip>
> I have 3 parameters h,m,n. Parameters m and n are integers. I tried
> to find inverse Laplace transform of function:
> InverseLaplaceTransform[-1/h - ((((-h+p)/(h+p))^(m-2n)) * (h+p)^2) /
> (h*(h-p)*p),p,x]
>
> *-*-*-*-*- Mathematica code *-*-*-*-*
>
> \!\(InverseLaplaceTransform[\(-\(1\/h\)\) - \(\((\(\(-h\) + p\)\/\(h +
> p\))\)\
> \^\(m - 2\ n\)\ \((h + p)\)\^2\)\/\(h\ \((h - p)\)\ p\), p, x]\)
>
> -*-*-*-*-*--*-*-*-*-*--*-*-*-*-*--*-*-*-*-*--*
>
> but mathematica can not give me an answer. Can it be solved by
> Mathematica?
Though I do not know if this solve your problem, you can add assumptions
to the InverseLaplaceTransform(like you can do with Integrate for
instance). At least the documentation says so but the Front-End
stubbornly (rightly?) colors everything after the x in flashy red...
InverseLaplaceTransform[-1/
h - ((((-h + p)/(h + p))^(m - 2 n))*(h + p)^2)/(h*(h - p)*p), p, x,
Assumptions -> {m, n} \[Element] Integers && m > 0 && n > 0]
HTH,
--
Jean-Marc