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Re: making a list using table but with different


Join[{0, 1}, Flatten[Table[Range[2, 10]*10^n, {n, 0, 1}]]]

{0,1,2,3,4,5,6,7,8,9,10,20,30,40,50,60,70,80,90,100}


Bob Hanlon

---- sean_incali <sean_incali at yahoo.com> wrote: 
> I can make a list using
> 
> Table[a, {a, 0, 100, 10}]
> 
> gives
> 
> {0, 10, 20, 30, 40, 50, 60, 70, 80, 90, 100}
> 
> 
> But let's say I wanted to make a list that increment in 1 up to 10,
> then increment in 10 onwards.
> 
> So that after "tabling" I would get...
> 
> {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 20, 30, 40, 50, 60, 70, 80, 90,
> 100}
> 
> How do I accomplish this?
> 
> 



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