Re: making a list using table but with different
- To: mathgroup at smc.vnet.net
- Subject: [mg81504] Re: [mg81469] making a list using table but with different
- From: Bob Hanlon <hanlonr at cox.net>
- Date: Wed, 26 Sep 2007 06:39:21 -0400 (EDT)
- Reply-to: hanlonr at cox.net
Join[{0, 1}, Flatten[Table[Range[2, 10]*10^n, {n, 0, 1}]]]
{0,1,2,3,4,5,6,7,8,9,10,20,30,40,50,60,70,80,90,100}
Bob Hanlon
---- sean_incali <sean_incali at yahoo.com> wrote:
> I can make a list using
>
> Table[a, {a, 0, 100, 10}]
>
> gives
>
> {0, 10, 20, 30, 40, 50, 60, 70, 80, 90, 100}
>
>
> But let's say I wanted to make a list that increment in 1 up to 10,
> then increment in 10 onwards.
>
> So that after "tabling" I would get...
>
> {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 20, 30, 40, 50, 60, 70, 80, 90,
> 100}
>
> How do I accomplish this?
>
>