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MathGroup Archive 2007

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Re: making a list using table but with different increment after

  • To: mathgroup at smc.vnet.net
  • Subject: [mg81538] Re: making a list using table but with different increment after
  • From: dh <dh at metrohm.ch>
  • Date: Wed, 26 Sep 2007 06:56:54 -0400 (EDT)
  • References: <fd7sae$cgl$1@smc.vnet.net>


Hi Sean,

here are some possibilities:

specify the values you want: Table[i,{i,{0,1,2,3,4,5,6,7,8,9,10,20,30}}]

make 2 Lists: Join[Table[i,{i,0,9}],Table[i,{i,10,100,10}]]

make 2 dim. list and flatten: Flatten[ Table[i 10^j,{j,0,1},{i,1,9}] ]

multiply "mantissa" with "exponent": Table[i,{2},{i,1,9}] 10^{0,1}

remember: there is more than one way to do things (like in Perl)

hope this helps, Daniel



sean_incali wrote:

> I can make a list using

> 

> Table[a, {a, 0, 100, 10}]

> 

> gives

> 

> {0, 10, 20, 30, 40, 50, 60, 70, 80, 90, 100}

> 

> 

> But let's say I wanted to make a list that increment in 1 up to 10,

> then increment in 10 onwards.

> 

> So that after "tabling" I would get...

> 

> {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 20, 30, 40, 50, 60, 70, 80, 90,

> 100}

> 

> How do I accomplish this?

> 

> 




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