Re: Nullcline and getting "2" values for y
- To: mathgroup at smc.vnet.net
- Subject: [mg81503] Re: [mg81468] Nullcline and getting "2" values for y
- From: DrMajorBob <drmajorbob at bigfoot.com>
- Date: Wed, 26 Sep 2007 06:38:49 -0400 (EDT)
- References: <28556801.1190690438836.JavaMail.root@m35>
- Reply-to: drmajorbob at bigfoot.com
A function of y has ONE value for each y. (By definition of the term
"function".)
What you mean to say, I think, is that there are two solutions to a
certain equation. You haven't mentioned any such equation specifically, =
but... if I have to guess, I'd say you mean something like
fun = (b c y - a y^n + y^(1 + n))/(b + y^n);
f == fun
f == (10 y - 11 y^5 + y^6)/(10 + y^5)
Solving for y in terms of f gives up to SIX solutions, none of which are
expressible in radicals:
roots = y /. Solve[f == fun, y] // ToRadicals
{Root[-10 f + 10 #1 + (-11 - f) #1^5 + #1^6 &, 1],
Root[-10 f + 10 #1 + (-11 - f) #1^5 + #1^6 &, 2],
Root[-10 f + 10 #1 + (-11 - f) #1^5 + #1^6 &, 3],
Root[-10 f + 10 #1 + (-11 - f) #1^5 + #1^6 &, 4],
Root[-10 f + 10 #1 + (-11 - f) #1^5 + #1^6 &, 5],
Root[-10 f + 10 #1 + (-11 - f) #1^5 + #1^6 &, 6]}
Plot[roots, {f, -5, 1}]
Plot[roots, {f, -50, 10}]
Plot omits complex results, so those give an incomplete picture of the
situation.
Bobby
On Mon, 24 Sep 2007 03:21:14 -0500, sean_incali <sean_incali at yahoo.com>
wrote:
> I have this equation I can plot using the following
>
> ClearAll["Global`*"]
>
>
> fun = (b c y - a y^ n + y^(1 + n))/(b + y^n);
> d = 0.1;
> c = 1;
> b = 10;
> a = 11;
> n = 5;
> ParametricPlot[{fun, (y)}, {y, 0, 1}, PlotRange -> All]
>
> I am plotting the function "fun" against values of y.
>
> When I do that I get a curvew that clearly shows that, for a given
> value of y, I should get two value for the function.
>
> How do I get what they are?
>
> If I just go..
>
> d = 0.1;
> c = 1;
> b = 10;
> a = 11;
> n = 2;
> y = 0.5;
>
> (b c y - a y^ n + y^(1 + n))/(b + y^n)
>
> I get
>
> 0.231707
>
> but starting at y=0 all the way to y= 0.6 or so, there are two values!
> (according to the graph)
>
> How do I get what those values are?
>
>
> Thanks for any input.
>
> sean
>
>
>
--
DrMajorBob at bigfoot.com