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Re: Nullcline and getting "2" values for y


sean_incali wrote:
> I have this equation I can plot using the following
> 
> ClearAll["Global`*"]
> 
> 
> fun = (b c y - a y^ n + y^(1 + n))/(b + y^n);
> d = 0.1;
> c = 1;
> b = 10;
> a = 11;
> n = 5;
> ParametricPlot[{fun, (y)}, {y, 0, 1}, PlotRange -> All]
> 
> I am plotting the function "fun" against values of y.
> 
> When I do that I get a curvew that clearly shows that, for a given
> value of y, I should get two value for the function.
> 
> How do I get what they are?
> 
> If I just go..
> 
> d = 0.1;
> c = 1;
> b = 10;
> a = 11;
> n = 2;
> y = 0.5;
> 
> (b c y - a y^ n + y^(1 + n))/(b + y^n)
> 
> I get
> 
> 0.231707
> 
> but starting at y=0 all the way to y= 0.6 or so, there are two values!
> (according to the graph)
> 
> How do I get what those values are?
> 
> 
> Thanks for any input.
> 
> sean

Sorry, but I don't really understand this ... You defined 'fun' to be a 
single valued function.  It has only a single value for any 'y' in {0,1} 
...

-- 
Szabolcs


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