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Re: PolarPlot


Dear Bruce,
It doesn't appear that you are plotting what you say you wish to.
If I understand correctly, you are asking for
a = 2;
PlotPlot[4 a^2 Cos@theta, {theta, 0, 2 Pi}]

In your example, you are plotting two radial functions. Perhaps you were
thinking of ParametricPlot?

On Fri, Apr 11, 2008 at 1:47 AM, Bruce Colletti <vze269bv at verizon.net>
wrote:

> Re 6.0.2 under WinXP.
>
> I'm using the command below to plot the polar equation r^2 = 4a^2
> Cos@theta.  Is there a better way?  Thankx.
>
> Bruce
>
> PolarPlot[{2 a Sqrt[Cos@t], -2 a Sqrt[Cos@t]}, {t, 0, 2 \[Pi]},
>  PlotRange -> 7]
>
>


-- 
W. Craig Carter



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