PolarPlot

*To*: mathgroup at smc.vnet.net*Subject*: [mg87484] PolarPlot*From*: Bruce Colletti <vze269bv at verizon.net>*Date*: Fri, 11 Apr 2008 01:47:39 -0400 (EDT)

Re 6.0.2 under WinXP. I'm using the command below to plot the polar equation r^2 = 4a^2 Cos@theta. Is there a better way? Thankx. Bruce PolarPlot[{2 a Sqrt[Cos@t], -2 a Sqrt[Cos@t]}, {t, 0, 2 \[Pi]}, PlotRange -> 7]

**Follow-Ups**:**Re: PolarPlot***From:*"W_Craig Carter" <ccarter@mit.edu>