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MathGroup Archive 2008

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PolarPlot

  • To: mathgroup at smc.vnet.net
  • Subject: [mg87484] PolarPlot
  • From: Bruce Colletti <vze269bv at verizon.net>
  • Date: Fri, 11 Apr 2008 01:47:39 -0400 (EDT)

Re 6.0.2 under WinXP.

I'm using the command below to plot the polar equation r^2 = 4a^2 Cos@theta.  Is there a better way?  Thankx.

Bruce

PolarPlot[{2 a Sqrt[Cos@t], -2 a Sqrt[Cos@t]}, {t, 0, 2 \[Pi]}, 
 PlotRange -> 7]


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