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Re: A Problem with Simplify
*To*: mathgroup at smc.vnet.net
*Subject*: [mg87515] Re: A Problem with Simplify
*From*: Alexey Popkov <popkov at gmail.com>
*Date*: Sat, 12 Apr 2008 06:56:50 -0400 (EDT)
*References*: <ftkb7f$a9m$1@smc.vnet.net> <ftmts8$4l5$1@smc.vnet.net>
On 11 =C1=D0=D2, 13:59, Jean-Marc Gulliet <jeanmarc.gull... at gmail.com>
wrote:
> Alexey Popkov wrote:
>
> <snip>
>
> > Recently I also have found another strange bug in Simplfy (not so
> > dangerous):
> > FullSimplify[Sin[x]*Cos[x]]
> > gives Sin[x]*Cos[x] instead Sin[2*x]/2. The workaround is
> > FullSimplify[2*Sin[x]*Cos[x]]/2.
>
> <snip>
>
> This is not a bug, indeed. As a rule of thumb, *FullSimplify* tries to
> minimize the leaf count of the expression.
>
> For the case above, the original expression sin(x)cos(x) has a leaf
> count of 5 whereas the trigonometric identity sin(2x)/2 has a leaf count
> of 8. Therefore, *FullSimplify* returns the original form sin(x)cos(x)
> since it is deemed as simpler than sin(2x)/2 w.r.t. the lead count of
> each expression.
>
> Note that, in general, you can modify/tweak this default behavior to
> suit your needs by witting your own *ComplexityFunction*. However, when
> dealing with trigonometric expressions (especially when looking for some
> trigonometric identities) it is usually better and less cumbersome to
> use *TrigReduce* and the like (*TrigExpand*, *TrigFactor*, etc.).
>
> FullSimplify[Sin[x]*Cos[x]] (* returns Cos[x] Sin=
[x] *)
> % // LeafCount (* returns =
5 *)
> TrigReduce[Sin[x]*Cos[x]] (* returns 1/2 Sin[=
2 x] *)
> % // LeafCount (* returns =
8 *)
> LeafCount[Cosh[x] - Sinh[x]] (* returns 7 =
*)
> FullSimplify[Cosh[x] - Sinh[x]] (* returns E^-x =
*)
> % // LeafCount (* returns =
5 *)
>
> Best regards,
> -- Jean-Marc
Big thanks! I did not understand this from the documentation. But now
this become clear.
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