Re: List concatenation - two more methods, one truly fast
- To: mathgroup at smc.vnet.net
- Subject: [mg87827] Re: List concatenation - two more methods, one truly fast
- From: carlos at Colorado.EDU
- Date: Fri, 18 Apr 2008 02:39:18 -0400 (EDT)
- References: <ftv8ro$7o1$1@smc.vnet.net> <fu7akb$f0t$1@smc.vnet.net>
> > This result is fascinating - it is reasonable that all the solutions > based on appending lists work O(n^2), but the nested list approach > should not behave this way. If you repeat the timing, but without > defining p: > > n = 5000; poly = Table[0, {n}]; > Print[Timing[Do[poly = {poly, p[i]}, {i, 1, n}]; > poly = Flatten[poly]][[1]]]; > > I get 0.02 seconds rather than 11 seconds (I obviously have a slightly > slower machine. This means that the time depends crucially on what you > are accumulating. > > Consider the semantics of the operation: > > poly = {poly, p[i]} > > This will only be efficient if Mathematica 'knows' that the old value of > poly is already fully evaluated. As I understand it, Mathematica does > this using a hashing method, and my guess is that in this case the hash > table overflows and the ever growing expression gets repeatedly > evaluated - hence O(n^2). > > It would be nice if someone from Wolfram could comment on these timing > results. > > Incidentally, the following method works efficiently without requiring > the array size to be known in advance: > > n = 5000; poly = Table[0, {n}]; > Print[Timing[poly = Reap[Do[Sow[p[i]], {i, 1, n}]][[2, 1]]][[1]]]; > > David Baileyhttp://www.dbaileyconsultancy.co.uk Note that O(n^2) dependence is a killer for building long object lists. For example suppose I increase n to 200000 polygons. In FEM work that is a medium size plot. Building the Show[] list by one of the O(n^2) methods extrapolates to about 50000 seconds (14 hours) on my desktop G5. And I know that on that machine elapsed time is about 3 times that reported by Timing[]. Waiting 40+ hours for one plot is not exactly interactive speed. On the other hand a O(n) scheme would build it in less than a second.
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- From: Daniel Lichtblau <danl@wolfram.com>
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