2*m^z - m^z = ?
- To: mathgroup at smc.vnet.net
- Subject: [mg88104] 2*m^z - m^z = ?
- From: Alexey Popkov <popkov at gmail.com>
- Date: Fri, 25 Apr 2008 05:26:33 -0400 (EDT)
Hello, What do you think about this: Table[ {2*m^z - m^z, FullSimplify[2*m^z - m^z]}, {m, 1, 21}] // TableForm The answer is very interesting (only odd numbers are treated well): 1 1 -2^z + 2^(1 + z) 2^z 3^z 3^z 2^(1 + 2*z) - 4^z 4^z 5^z 5^z 2^(1 + z)*3^z - 6^z 2^(1 + z)*3^z - 6^z 7^z 7^z 2^(1 + 3*z) - 8^z 8^z 9^z 9^z 2^(1 + z)*5^z - 10^z 2^(1 + z)*5^z - 10^z 11^z 11^z 2^(1 + 2*z)*3^z - 12^z 2^(1 + 2*z)*3^z - 12^z 13^z 13^z 2^(1 + z)*7^z - 14^z 2^(1 + z)*7^z - 14^z 15^z 15^z 2^(1 + 4*z) - 16^z 16^z 17^z 17^z 2^(1 + z)*9^z - 18^z 2^(1 + z)*9^z - 18^z 19^z 19^z 2^(1 + 2*z)*5^z - 20^z 2^(1 + 2*z)*5^z - 20^z 21^z 21^z Can anyone explain the reason for this behavior?
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- Re: 2*m^z - m^z = ?
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