Re: Complex Plot
- To: mathgroup at smc.vnet.net
- Subject: [mg88288] Re: Complex Plot
- From: Jean-Marc Gulliet <jeanmarc.gulliet at gmail.com>
- Date: Wed, 30 Apr 2008 07:03:23 -0400 (EDT)
- Organization: The Open University, Milton Keynes, UK
- References: <fv9a83$mjo$1@smc.vnet.net>
Chris Degnen wrote: > Can anyone tell me how I can re-express this > equation in terms of x for plotting? > > Sin[x^2*y]==Log[x/y] > > last sighted: http://tinyurl.com/3s4hfd Hi Chris, If you are interested in the graphical representation of this function, you may want to use *ContourPlot* and experiment with its various options. For instance, ContourPlot[Sin[x^2*y] - Log[x/y], {x, -12, 35}, {y, -8, 23}, ImageSize -> 500] ContourPlot[Sin[x^2*y] - Log[x/y], {x, -12, 35}, {y, -8, 23}, ImageSize -> 500, ColorFunction -> (White &), ContourStyle -> Black, MaxRecursion -> 0, PlotPoints -> 500] You can see the result at http://homepages.nyu.edu/~jmg336/mathematica/chrisdegnencomplexplot.pdf Note that the second plot may take several minutes to complete due to the huge number of sampling points, but it should be very close to what you have seen on the Internet. Hope this helps, -- Jean-Marc