Re: evaluations in Plot in Manipulate?
- To: mathgroup at smc.vnet.net
- Subject: [mg91033] Re: evaluations in Plot in Manipulate?
- From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
- Date: Mon, 4 Aug 2008 03:23:19 -0400 (EDT)
- Organization: Uni Leipzig
- References: <g6kc15$k4d$1@smc.vnet.net>
- Reply-to: kuska at informatik.uni-leipzig.de
Hi,
you miss, that Manipulate[] by default localize the variables
and in
expr=Exp[a]
Manipulate[
Exp[a],{a,1,5}]
a in expr is not the same as "a" in Manipulate[]. You can see this
when you type
Manipulate[HoldForm[a], {a, 1, 5}]
The option LocalizeVariables control the generation of local variables.
Regards
Jens
J Davis wrote:
> I must be overlooking something simple in the way Mathematica handles
> the arguments of Manipulate.
>
> Could someone expound on the contrast in behavior between the last
> example below and the previous two?
>
> Clear[a, b, c, h];
> a = 1;
> c = 1;
> h[t_] = InverseLaplaceTransform[1/(a s^2 + b s + c), s, t]
>
>
> Manipulate[
> Plot[Evaluate[
> InverseLaplaceTransform[1/(a s^2 + b s + c), s, t]], {t, 0, 10},
> PlotRange -> {{0, 10}, {-1, 1}}], {b, 0, 5}]
>
> (* works fine *)
>
>
> Manipulate[
> Plot[-((E^((-(b/(2 a)) - Sqrt[b^2 - 4 a c]/(2 a)) t) -
> E^((-(b/(2 a)) + Sqrt[b^2 - 4 a c]/(2 a)) t))/Sqrt[
> b^2 - 4 a c]), {t, 0, 10}, PlotRange -> {{0, 10}, {-1, 1}}], {b, 0,
> 5}]
>
> (* works fine... I just copied and pasted the output of h[t] into the
> Plot[...] *)
>
>
> Manipulate[
> Plot[Evaluate[h[t]], {t, 0, 10},
> PlotRange -> {{0, 10}, {-1, 1}}], {b, 0, 5}]
>
> (* nothing... what am I missing? *)
>
> Doesn't Evaluate[h[t]] hold the evaluated form of h[t] (so that it is
> computed just once) and then Plot simply substitutes a sequence of
> numerical values into that evaluated form? If so, why is there no
> output?
>
> Thanks in advance,
> John
>