Re: a question
- To: mathgroup at smc.vnet.net
- Subject: [mg94359] Re: a question
- From: Miguel <misvrne at gmail.com>
- Date: Thu, 11 Dec 2008 03:44:12 -0500 (EST)
- References: <ghnfjh$nlv$1@smc.vnet.net> <gho4l7$v9$1@smc.vnet.net>
On 10 dic, 11:11, "sjoerd.c.devr... at gmail.com"
<sjoerd.c.devr... at gmail.com> wrote:
> Hi Alberto,
>
> I would say that Mathematica is correct in not showing the
> discontinuity at x=3/2 as it is infinitesimally small. The gap is
> infinitely smaller than any screen pixel in which it is contained, so
> it can't be shown.
>
> However,
>
> Plot[((4 x - 6)/(3 - 2 x)), {x, 1, 2}, Exclusions -> {x == 3/2},
> Frame -> True, Axes -> None]
>
> provides you with a line with a gap at x=3/2.
>
> Cheers -- Sjoerd
>
> On Dec 10, 6:12 am, alberto gonzalez<seriasoneubanitne... at yahoo.com.ar> w=
rote:
> > hi people of mathgroup! i hope youre ok !im alberto from argentina im a=
m=
>
> athematica user and=C2 i have a question:> i tried a lot of ways to =
plot y=4x-6/3-2x and i cant get to make it not=
>
> iced in the plot the hole of discontinuity that the sketch presents a whe=
n =
> the function turns to P(3/2,-2).the best aproximation ive gotten is
>
> > Plot[((4 x-6)/(3-2 x)),{x,1,2},PlotPloints->2]
> > could you help to me please?
> > thanks
I think there is no discontinuity. If you trie to use Simplify
In[]: Simplify[f[x]]
Out[]: -2
It is a line paralell to X axis.