Re: a question
- To: mathgroup at smc.vnet.net
- Subject: [mg94345] Re: a question
- From: "sjoerd.c.devries at gmail.com" <sjoerd.c.devries at gmail.com>
- Date: Wed, 10 Dec 2008 05:11:57 -0500 (EST)
- References: <ghnfjh$nlv$1@smc.vnet.net>
Hi Alberto,
I would say that Mathematica is correct in not showing the
discontinuity at x=3/2 as it is infinitesimally small. The gap is
infinitely smaller than any screen pixel in which it is contained, so
it can't be shown.
However,
Plot[((4 x - 6)/(3 - 2 x)), {x, 1, 2}, Exclusions -> {x == 3/2},
Frame -> True, Axes -> None]
provides you with a line with a gap at x=3/2.
Cheers -- Sjoerd
On Dec 10, 6:12 am, alberto gonzalez
<seriasoneubanitne... at yahoo.com.ar> wrote:
> hi people of mathgroup! i hope youre ok !im alberto from argentina im a m=
athematica user and=C2 i have a question:
> i tried a lot of ways to plot y=4x-6/3-2x and i cant get to make it not=
iced in the plot the hole of discontinuity that the sketch presents a when =
the function turns to P(3/2,-2).the best aproximation ive gotten is
> Plot[((4 x-6)/(3-2 x)),{x,1,2},PlotPloints->2]
> could you help to me please?
> thanks