Re: Re: Mathematica 6 -> Mathematica 7, Histogram problem
- To: mathgroup at smc.vnet.net
- Subject: [mg94922] Re: [mg94882] Re: Mathematica 6 -> Mathematica 7, Histogram problem
- From: Bob Hanlon <hanlonr at cox.net>
- Date: Tue, 30 Dec 2008 05:55:54 -0500 (EST)
- Reply-to: hanlonr at cox.net
Histogram[Range[Length[vector]] - 1, Length[vector], vector &, PlotRange -> All] Bob Hanlon ---- Richard Trilling <trilling at orange.fr> wrote: ============= Thank you, "Bob Hanlon" <hanlonr at cox.net> wrote in message news:gj55id$c5e$1 at smc.vnet.net... > vector = {4, 4, 16, 17, 7, 9, 10, 20, 5, 9}; > > data = Flatten[ > Inner[Table[#1, {#2}] &, Range[Length[vector]] - 1, vector, List]]; > Histogram[data, Length[vector]] > > Histogram[Range[Length[vector]] - 1, Length[vector], vector &] > > Bob Hanlon Thank you I'm using the second method: Histogram[Range[Length[vector]] - 1, Length[vector], vector &] because it's simpler and because the first method only applies to a vector of integers, which my vector is not. This leads to another problem: The first two columns of my histogram are cut off, placing the cursor over the column gives the correct value except that they don't show on the graph. What to do? Is this a bug? I need them to show. Is there some way to force this? The vector I'm using is: vector = {0.504644, 0.344778, 0.194196, 0.114043, 0.0873715, 0.0889029, 0.088267, 0.0848237, 0.0631136, 0.0471143} Thank you again (or anybody else), in advance, Richard Trilling