Re: Reduce in Ver 6

*To*: mathgroup at smc.vnet.net*Subject*: [mg85502] Re: Reduce in Ver 6*From*: "Dana DeLouis" <dana.del at gmail.com>*Date*: Wed, 13 Feb 2008 04:07:01 -0500 (EST)

> Use the Backsubstitution -> True setting for Reduce[] Darn! Yep! Right there in help under Reduce. Thank you very much. I think I've been confusing this with the "VerifySolutions" option under Solve. I now understand my mistake. Can't believe I've missed this all this time. Thanks again. equ = {a + b + c == 3, a^2 + b^2 + c^2 < 10, a^3 + b^3 + c^3 == 15, a^4 + b^4 + c^4 == 35}; sol = {ToRules[Reduce[equ, {a, b, c}, Backsubstitution -> True]]}; Simplify[a^5 + b^5 + c^5 /. sol] {83, 83, 83, 83, 83, 83} -- Dana DeLouis <snip> >> I use Reduce, but 'c is returned as a function of a & b. >> What I would like is for c to replace a & b with the appropriate values. >> >> r = {ToRules[Reduce[equ, {a, b, c}]]} >> >> {{a -> 1, b -> 1 - Sqrt[2], c -> 3 - a - b}, > Use the Backsubstitution -> True setting for Reduce[] > > Szabolcs