Re: Making a lists with conditions
- To: mathgroup at smc.vnet.net
- Subject: [mg85703] Re: Making a lists with conditions
- From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
- Date: Tue, 19 Feb 2008 07:05:48 -0500 (EST)
- Organization: Uni Leipzig
- References: <fpduuo$rd3$1@smc.vnet.net>
- Reply-to: kuska at informatik.uni-leipzig.de
Hi,
get[lst_, key_] := First[Select[lst, MatchQ[#, {key, _}] &]]
ff[lst1_, lst2_] :=
If[! MemberQ[lst2, {#, _}], {#, 0}, get[lst2, #]] & /@ lst1
may help or
get1[lst_, key_] :=
Module[{elem},
elem = Select[lst, MatchQ[#, {key, _}] &];
If[{} === elem, {key, 0},
elem[[1]]
]
]
ff1[lst1_, lst2_] := get1[lst2, #] & /@ lst1
Regards
Jens
Guillermo Sanchez wrote:
> Dear group
>
> I have two list (list1:{a1, ...ai, aj, ..., an}, list2:{{ai,
> bi}, ..., {aj, bj}}.
>
> I wish to obtain a new list (list3} where be included all members of
> list1 and list2. If elements ak is not included in list2 then write
> {ak, 0}.
>
> Here is an example:
>
> list1 = {3.8, 3.85, 3.9, 3.95, 4., 4.05, 4.1};
> list2 = {{3.85, 120}, { 4.0 , 111}, {4.1, 314}};
>
> ff[list1_, list2_] := =BFlist1, list2?
>
>
> Here is the ouput that I wist to obtain
>
> Out:={{3.8, 0} , {3.85`, 120}, {3.9`, 0}, {3.95, 0}, {4.`, 111},
> {4.05`, 0}, {4.1`, 314}}
>
> I have a method but it is two complicate. I am sure that some members
> of the group will find a elegant solution
>
> Thanks
>
> Guillermo
>