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Re: Bug in Default[] or Bug in My Understanding?
- To: mathgroup at smc.vnet.net
- Subject: [mg89312] Re: Bug in Default[] or Bug in My Understanding?
- From: Jean-Marc Gulliet <jeanmarc.gulliet at gmail.com>
- Date: Thu, 5 Jun 2008 00:43:34 -0400 (EDT)
- Organization: The Open University, Milton Keynes, UK
- References: <g1m8ea$i2$1@smc.vnet.net>
Salvatore Mangano wrote:
> In[208]:= ClearAll[f] ;
> Default[f,2] = 0;
>
> In[210]:= f[a_, b_.] := a + b
>
> In[211]:= f[1]
> Out[211]= 1
>
> In[212]:= (* Now change Default *)
> Default[f,2] = 1;
>
> (* Note that Mathematica seems to recognize change *)
> In[213]:= ?f
> Global`f
> f[a_,b_.]:=a+b
>
> f/:Default[f,2]=1
>
>
> (* But not really! Expected 2 *)
> In[214]:= f[1]
> Out[214]= 1
>
> Even if it is a rule that you can't change the Default after the function is defined it is certainly not nice of Mathematica to allow such a change and advertise the change in the output of Definition[] and Information[].
>
> I am using 6.0.2.0 on Windows XP.
No bug here. The "more information" section of the online help for
*Default[]* reads "The necessary values for Default[f] must always be
defined before _. is used as an argument of f."
The following works as expected:
In[25]:= ClearAll[f];
Default[f, 2] = 0;
f[a_, b_.] := a + b
f[1]
ClearAll[f];
Default[f, 2] = 1;
f[a_, b_.] := a + b
f[1]
Out[28]= 1
Out[32]= 2
Regards,
-- Jean-Marc
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