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Re: Log(ln) Function + 2 Parameters + Greater
*To*: mathgroup at smc.vnet.net
*Subject*: [mg89318] Re: Log(ln) Function + 2 Parameters + Greater
*From*: Bill Rowe <readnews at sbcglobal.net>
*Date*: Thu, 5 Jun 2008 00:44:41 -0400 (EDT)
On 6/4/08 at 5:37 AM, vexie.infamous at googlemail.com (Felipe
Mannshardt) wrote:
>Thanks for all replies, worked for my last function, but the
>suggestions you guys made so far did work with my last function, but
>now i have a new one, and i am here just playing around and i am
>unable to get it drawn :(
>First to the first Function, i believe the best suggestion was the
>use of "if",
>But, i can not get it to work :/
>Clear[x, f, a]
>f[a_][x_] := x (a + Log[x])^2
>If[a > 0, Plot[f[x], {x, 0, 2}]]
Since a is not defined, Mathematica cannot determine whether a
is greater than zero or not. Consequently, the If statement is
returned unevaluated.
>And all suggestions also did not work at all for my new Function,
>f[a_][x_] := (x/E^(ax));
>Plot[Table[f[a, x], {a, 0, 2}], {x, 0, 3}]
>What am i doing wrong ?
Simply put you are not being consistent. If you define f using
the form f[a_][x_] then you need to use this form when plotting.
That is,
f[a_][x_] := (x/E^(ax));
Plot[Table[f[a][x], {a, 0, 2}], {x, 0, 3}]
should give you the plot you are expecting. Or you could get the
same result with
f[a_, x_] := (x/E^(ax));
Plot[Table[f[a, x], {a, 0, 2}], {x, 0, 3}]
Notice, I use the same form for Plot as I used to define the function.
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