- To: mathgroup at smc.vnet.net
- Subject: [mg89329] Integral Questions
- From: "Graeme Dennes" <gdennes at bigpond.com>
- Date: Fri, 6 Jun 2008 06:45:22 -0400 (EDT)
I am attempting to calculate the integrals with respect to x of the two
x^2 + a
arcsin (---------) - c
2. As above, squared.
where a, b, c are constants.
Mathematica 6 presents solutions which seem to depend on the form of the
function entered, and in some instances, Mathematica does not read the
Eg, using ((x^2 + a)/(bx)) and (x/b + a/b/x) as different (but correct)
forms of the arcsin function yield different results!
Taking the first function, and entering it as:
The answer presented is: - a arcsin arcsin x
-------- + -------- - c Log (x)
Note the missing argument of the first arcsin.
As noted, different results can be provided for different (but correct!)
forms of the entered function. I do not understand why this would be so.
1. Are there (true) closed form solutions to both functions 1 and 2?
2. Is there some technique required to cause Mathematica to read the syntax
3. Is there some technique required to cause Mathematica to provide the
correct solution, assuming a closed form solution exists?
If the answer to Q1 is NO, then that would explain why the correct answer is
Any advice with this issue would be much appreciated.
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