Re: FindROot and substitutions

• To: mathgroup at smc.vnet.net
• Subject: [mg89884] Re: FindROot and substitutions
• From: Jean-Marc Gulliet <jeanmarc.gulliet at gmail.com>
• Date: Tue, 24 Jun 2008 03:20:32 -0400 (EDT)
• Organization: The Open University, Milton Keynes, UK
• References: <g3ihp3\$fd5\$1@smc.vnet.net> <g3kus2\$7hn\$1@smc.vnet.net> <g3nh71\$cu\$1@smc.vnet.net>

```Aaron Fude wrote:

> Thanks.
>
> Just one follow up question. How was it that the semicolon told you
> that I didn't understand something? I thought it just meant "suppress
> output" or "compound expression".
>
> Thanks again.

It is good practice to quote the relevant part of the message to whom
you are responding to. Here I can just imagine that you are referring to
the following (note that I am not the original poster, so I speak for
myself about my interpretation of the original poster's thought!):

ï¿½ wrote:
> Aaron Fude wrote:
>> Hi,
>>
>> I have found a workaround for this problem, but I would like to
>> understand how Mathematica wants you to think so I'm asking the
>> question anyway.
>>
>> Why does "bad" not work, while "good" works?
>>
>> g := x z;
>
> ----------^
> You used a semicolon here, so I suppose that you do not understand the
> difference between SetDelayed and Set.

The above expression is not a compound expression.

SetDelayed does not produce any output.

Therefore the semicolon is not needed and does not change anything.

So someone may infer that you do not have a clear idea about about the
differences between immediate and delayed assignments, which are topics