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Re: FindROot and substitutions

• To: mathgroup at smc.vnet.net
• Subject: [mg89884] Re: FindROot and substitutions
• From: Jean-Marc Gulliet <jeanmarc.gulliet at gmail.com>
• Date: Tue, 24 Jun 2008 03:20:32 -0400 (EDT)
• Organization: The Open University, Milton Keynes, UK
• References: <g3ihp3$fd5$1@smc.vnet.net> <g3kus2$7hn$1@smc.vnet.net> <g3nh71$cu$1@smc.vnet.net>

Aaron Fude wrote:

> Thanks.
> 
> Just one follow up question. How was it that the semicolon told you
> that I didn't understand something? I thought it just meant "suppress
> output" or "compound expression".
> 
> Thanks again.

It is good practice to quote the relevant part of the message to whom 
you are responding to. Here I can just imagine that you are referring to 
the following (note that I am not the original poster, so I speak for 
myself about my interpretation of the original poster's thought!):

� wrote:
 > Aaron Fude wrote:
 >> Hi,
 >>
 >> I have found a workaround for this problem, but I would like to
 >> understand how Mathematica wants you to think so I'm asking the
 >> question anyway.
 >>
 >> Why does "bad" not work, while "good" works?
 >>
 >> g := x z;
 >
 > ----------^
 > You used a semicolon here, so I suppose that you do not understand the
 > difference between SetDelayed and Set.

The above expression is not a compound expression.

SetDelayed does not produce any output.

Therefore the semicolon is not needed and does not change anything.

So someone may infer that you do not have a clear idea about about the 
differences between immediate and delayed assignments, which are topics 
of some importance to answer the rest of your original question.

Best regards,
-- Jean-Marc