Re: delta function

*To*: mathgroup at smc.vnet.net*Subject*: [mg89957] Re: delta function*From*: Roman <rschmied at gmail.com>*Date*: Wed, 25 Jun 2008 06:26:49 -0400 (EDT)*References*: <g3ihpo$fdt$1@smc.vnet.net>

Magician, I don't know an answer to your question; however, the function with the proper limit is Exp[-(x-xo)^2/t]/Sqrt[Pi*t] and not the one you specify. You can check this with Integrate[Exp[-(x-xo)^2/t]/Sqrt[Pi*t], {x,-Infinity,Infinity}, Assumptions -> t>0] which gives you 1 for all values of t; this is what the Dirac delta- function requires. Roman. On Jun 21, 11:31 am, Magician <jadoo.d... at gmail.com> wrote: > I am integrating over a function (not written in mathematica syntax) > > u=F(x) e^(- (x-xo)^2/t ) /t , > i know in the limit t ->0, e^(- (x-xo)^2/t ) /t = delta(x-xo), but > how do i get mathematica to recognize this. > > In mathematica, how can i construct hings like the Sokhotskyi-Plemelj > formula ?