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Re: ContourPlot problem
*To*: mathgroup at smc.vnet.net
*Subject*: [mg90087] Re: ContourPlot problem
*From*: "David Park" <djmpark at comcast.net>
*Date*: Sat, 28 Jun 2008 05:53:34 -0400 (EDT)
*References*: <g42ere$no5$1@smc.vnet.net>
ContourPlot often requires a specification of the "z" plot range, else
Mathematica will select what it thinks is the best PlotRange. This will
often be less than you want. So the following will work:
ContourPlot[Exp[-x^2 - 2 y^2], {x, -3, 3}, {y, -3, 3},
Contours -> {.1, .2, .3, .4, .5, .6, .7, .8, .9, 1},
ContourLabels -> True, ContourShading -> False,
PlotRange -> {0, 1.1}]
--
David Park
djmpark at comcast.net
http://home.comcast.net/~djmpark/
"Jorge Cortes" <jcormon at gmail.com> wrote in message
news:g42ere$no5$1 at smc.vnet.net...
> Hello,
>
> I've noticed the following problem with ContourPlot (I'm using
> Mathematica 6..0.3) and a simple exponential function.
>
> If you try the domain {x,-3,3}, {y,-3,3}
>
> ContourPlot[Exp[-x^2 - 2 y^2], {x, -3,3}, {y, -3, 3},
> Contours -> {.1,.2, .3, .4, .5, .6, .7, .8, .9, 1},
> ContourLabels -> True, ContourShading -> False]
>
> you only get one contour (the one corresponding to .1). However, if
> you shrink the domain to {x,-2,2}, {y,-2,2}, surprisingly you get all
> the contours (?)
>
> ContourPlot[Exp[-x^2 - 2 y^2], {x, -2,2}, {y, -2, 2},
> Contours -> {.1,.2, .3, .4, .5, .6, .7, .8, .9, 1},
> ContourLabels -> True, ContourShading -> False]
>
> Does anybody has an explanation for this? Thanks!
>
> - Jorge
>
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