Re: ContourPlot problem

*To*: mathgroup at smc.vnet.net*Subject*: [mg90082] Re: ContourPlot problem*From*: "Jorge Cortes" <jcormon at gmail.com>*Date*: Sat, 28 Jun 2008 05:52:38 -0400 (EDT)*References*: <g42ere$no5$1@smc.vnet.net> <4864E1C8.90204@gmail.com>

Thank you! I sent the answer below also to David, and forgot to CC the group, just in case: **** Thanks much! What i don't like so much is that, with ContourShading->True, the appearance of the plot changes substantially depending on the range in PlotRange -- plus, you're supposed to know the min and max of the function a priori :-) **** On Fri, Jun 27, 2008 at 5:49 AM, Jean-Marc Gulliet < jeanmarc.gulliet at gmail.com> wrote: > Jorge Cortes wrote: > > I've noticed the following problem with ContourPlot (I'm using >> Mathematica 6..0.3) and a simple exponential function. >> >> If you try the domain {x,-3,3}, {y,-3,3} >> >> ContourPlot[Exp[-x^2 - 2 y^2], {x, -3,3}, {y, -3, 3}, >> Contours -> {.1,.2, .3, .4, .5, .6, .7, .8, .9, 1}, >> ContourLabels -> True, ContourShading -> False] >> >> you only get one contour (the one corresponding to .1). However, if >> you shrink the domain to {x,-2,2}, {y,-2,2}, surprisingly you get all >> the contours (?) >> > > <snip> > > Specifying PlotRange -> {-2, 2} or PlotRange -> {-3, 3} will show > everything. For instance, > > ContourPlot[Exp[-x^2 - 2 y^2], {x, -3, 3}, {y, -3, 3}, > Contours -> {.1, .2, .3, .4, .5, .6, .7, .8, .9, 1}, > ContourLabels -> True, ContourShading -> False, PlotRange -> {-3, 3}] > > Regards, > -- Jean-Marc >