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Re: nesting pure functions

On Feb 29, 5:43=A0am, Ryan Olf <r... at> wrote:
> I have figured out how to do this in one manner. What I want is this:
> g = Function[{x,y,f},f[x,y,#]&]
> Now, the question remains: is there a way to do this without naming
> variables explicitly? I would not be surprised if the answer is no.
> Ryan
> Ryan Olf wrote:
> > I'm trying to define a function, g, such that given some parameters and
> > a function as arguments, it returns a pure function:
> > g[x_,y_,f_Function] = Function[f[x,y,#]]
> > However, I need to define g itself as a pure function. I'm not sure how
> > to do this. It may be something like this:
> > g = Function[Function[#3[#1,#2,#?????]]]
> > Obviously, I want #?????? to be the argument of the of the outermost
> > Function, and #1, #2, #3 of the innermost function.
> > Is there a way of defining g as a pure function (of a pure function) in
> > Mathematica?
> > I appreciate your help,
> > Ryan

If you're asking, is there a way to write this using the #& notation,
I think the answer is no.  You'd like to write something similar to

(#3[#1, #2, #] &) &


Function[Function[#3[#1, #2, #]]]

but these are both incorrect; you intend for #1,#2,#3 to refer to the
parameters of the outer Function, but they do not.

As you pointed out, you can write

Function[{x, y, f},
 Function[f[x, y, #]]]

to get what you want.  This seems like the best solution; although
some of the variables are named, Function localizes variable names, so
you won't have to worry about name conflicts.  An alternative might be
to redefine the functions f that you're interested in using.  Right
now you call them with a sequence of three arguments: f[x,y,z].  If
you called them like this instead: f[x,y][z], then you could write

#3[#1, #2] &

which would be called like

(#3[#1, #2] & [x, y, f]) [z]

Hopefully that helps at least a little bit; good luck with your


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