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definite integration of 1/a


In[1]:=
Integrate[1/a,{a,1,ablah},Assumptions\[RuleDelayed]ablah>0]

Out[1]=
\!\(If[ablah > 1, Log[ablah],
    Integrate[1\/a, {a, 1, ablah},
      Assumptions \[Rule] ablah \[LessEqual] 1]]\)

I was expecting 1/a. Is there something I can do to get that? Thank you.

-- 
http://chris.chiasson.name/



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