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MathGroup Archive 2008

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definite integration of 1/a

  • To: mathgroup at smc.vnet.net
  • Subject: [mg86397] definite integration of 1/a
  • From: "Chris Chiasson" <chris at chiasson.name>
  • Date: Mon, 10 Mar 2008 02:04:56 -0500 (EST)

In[1]:=
Integrate[1/a,{a,1,ablah},Assumptions\[RuleDelayed]ablah>0]

Out[1]=
\!\(If[ablah > 1, Log[ablah],
    Integrate[1\/a, {a, 1, ablah},
      Assumptions \[Rule] ablah \[LessEqual] 1]]\)

I was expecting 1/a. Is there something I can do to get that? Thank you.

-- 
http://chris.chiasson.name/



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